Advent of Code 2024

Let’s do this (Advent of Code) thing again!

I’m sticking with Rust again. I still use Python when I need to hammer out something quickly, but if I want to do something correctly (and especially if I want it to be fast), you can’t beat Rust.

Let’s see how it goes!

Full solutions will once again be posted to GitHub (including previous years and possibly some I haven’t written up yet): jpverkamp/advent-of-code

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AoC 2023 Day 22: Block Dropinator

Source: Day 22: Sand Slabs

Full solution for today (spoilers!)

Part 1

Given a series of 3D blocks, allow them to fall until the simulation is stable. Any cube of a block is sufficient to support another block, ignore rotations etc.

How many blocks are not the sole supporter for any other block?

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AoC 2023 Day 20: Flip-Flopinator

Source: Day 20: Pulse Propagation

Full solution for today (spoilers!)

Part 1

Simulate a virtual circuit with high and low pulses and four kinds of chips:

  • Broadcast - Re-transmit all pulses
  • Flip-flops - On a low pulse, toggle internal state; if it was on, send high; otherwise send low
  • Conjunction - Remember input from each attached module; if all inputs were high, send a low, otherwise send high
  • Output - Do nothing; just receive pulses

Count the product of low and high pulses sent after 1000 low inputs to broadcaster.

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AoC 2023 Day 19: Assembly Lininator

Source: Day 19: Aplenty

Full solution for today (spoilers!)

Part 1

You are given a series of parts with 4 ratings as such:

{x=787,m=2655,a=1222,s=2876}

In addition, you are given a series of rules describing a graph as such:

px{a<2006:qkq,m>2090:A,rfg}

In this example, if you are at the node px, if a < 2006, move to qkq. Otherwise, if m > 2090 move to A. If no other case matches, the last defaults to rfg.

A and R are special cases for accept and reject.

Calculate the sum of sum of all four ratings for all nodes that end at Accept.

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