# AoC 2016 Day 20: Filter Table

### Source: Firewall Rules

Part 1: Given a list of integer ranges (a la 5-8), what is the first value not in any given range?

Most of this problem actually came down to making a relatively complicated data structure that can take an arbitrary number of overlapping ranges and simplify them, also allowing the addition and removal of more ranges. It’s more complicated than it strictly needs to be, but it makes this problem much easier. :)

class IntRange(object):
'''
Represents a list of integers.

Specific values can be allowed (included) / denied (excluded) from the range.
'''

def __init__(self, min, max):
'''Create a new int range with the given values initially allowed.'''

self._ranges = [(min, max)]

def __repr__(self):
'''Pretty print a range (this can get long).'''

return 'IntRange<{}>'.format(self._ranges)

def __in__(self, value):
'''Test if a value is in this int range.'''

# Slower version
# return any(lo <= value <= hi for (lo, hi) in self._ranges)

index = bisect.bisect(self._ranges, (value, value))
lo, hi = self._ranges[index]
return lo <= value <= hi

def __iter__(self):
'''Return all values in this int range.'''

for (lo, hi) in self._ranges:
yield from range(lo, hi + 1)

def __len__(self):
'''Return how many values are in this IP range.'''

return sum(hi - lo + 1 for (lo, hi) in self._ranges)

def _simplify(self):
'''Go through current ranges and remove/collapse overlapping ranges.'''

i = 0
while i + 1 < len(self._ranges):
range1_lo, range1_hi = self._ranges[i]
range2_lo, range2_hi = self._ranges[i + 1]

# Only guarantee: lo1 is <= lo2

# There is an overlap, combine and remove range2
# Continue without incrementing since another range might be collapsed
if range2_lo <= range1_hi:
self._ranges[i] = (range1_lo, max(range1_hi, range2_hi))
del self._ranges[i + 1]
continue

i += 1

def allow(self, allow_min, allow_max):
'''Add a new range of allowed values.'''

# Insert sorted (using bisect) then simplify
bisect.insort(self._ranges, (allow_min, allow_max))
self._simplify()

def deny(self, deny_min, deny_max):
'''Remove a range of (possibly) previously allowed values.'''

i = 0
while i < len(self._ranges):
lo, hi = self._ranges[i]

# Range is completely denied
if deny_min <= lo <= hi <= deny_max:
del self._ranges[i]
continue

# Denial is completely within the range, split it
elif lo <= deny_min <= deny_max <= hi:
del self._ranges[i]
self._ranges.insert(i, (lo, deny_min - 1))
self._ranges.insert(i + 1, (deny_max + 1, hi))

# Partial overlap, adjust the range
elif lo <= deny_min <= hi:
self._ranges[i] = (lo, deny_min - 1)

elif lo <= deny_max <= hi:
self._ranges[i] = (deny_max + 1, hi)

i += 1

The interesting functions there are:

• allow where I use the bisect module to insert elements into a sorted position in a list
• _simplify where I take a sorted list and combine overlapping adjacent elements (as part of allow)
• deny where I iterate through the list and remove/combine existing ranges that have been deleted or broken apart

deny took the most time, but it was still relatively straight forward.

lo, hi = map(int, args.range.split('-'))
ips = IntRange(lo, hi)

for line in fileinput.input(args.files):
if line:
lo, hi = map(int, line.split('-'))
ips.deny(lo, hi)

for ip in ips:
print('First allowed IP: {}'.format(ip))
break

Part 2: How many numbers are there between 0 and 2^32-1 (inclusive) are not in any range?

We already solved this with the __len__ method of IntRange:

print('Number of allowed IPs: {}'.format(len(ips)))

Interesting aside: You could probably do this with Python’s built in ipaddress module, specifically using a list of ipaddress.IPv4Network . I thought it was interesting to work out myself though.