Source: Security Through Obscurity1
Part 1: A room is described as a name, a sector ID, and a checksum as follows:
aaaaa-bbb-z-y-x-123[abxyz]
name: aaaaa-bbb-z-y-x sector ID: 123 checksum: abxyz
e>The next thing we want to do is generate a checksum (so we can see if it’s correct):
def generate_checksum(name):
'''
Custom checksum function by sorting all characters in the input on a tuple
of: length (shortest first) and the letter itself for alphabetical sorting.
'''
return ''.join(list(sorted(
set(name) - {'-'},
key = lambda letter : (
-name.count(letter),
letter
)
)))[:5]
Specifically, we’re going to create a list of letters in the string (removing dashes), then order them with a custom key: how many times they occur in the string. Negate this number so that we get the most first, and then put it in a tuple of (-count, letter) so that ties are broken by the letter. We couldn’t just reverse the list since the count is sorted descending and the letters ascending.
Combined the two by checking if checksum is valid:
valid_sector_id_sum = 0
with open(args.input_file, 'r') as fin:
for room in fin:
m = re.match(r'([a-z-]+)-(\d+)\[([a-z]+)\]', room)
name, sector_id, checksum = m.groups()
if checksum != generate_checksum(name):
continue
valid_sector_id_sum += int(sector_id)
print('sum of valid ids:', valid_sector_id_sum)
And we’re good to go.
Part 2: Decrypt the ‘real name’ of each room by applying a Caesar cipher with the sector ID. Find the ID containing ‘North Pole objects’.
What exactly a ‘North Pole object’ is isn’t yet clear, but we can write the decryption function easily enough:
def decrypt(name, key):
'''Shift all characters in the name by key positions.'''
offset = ord('a')
def shift(c):
if c == '-':
return ' '
else:
return chr((ord(c) - offset + key) % 26 + offset)
return ''.join(map(shift, name))
Since ASCII characters don’t start with a = 0 or a = 1 (but rather a = 97), we have to offset the characters by that much before applying the subtraction modulo 26. It works though:
>>> decrypt('qzmt-zixmtkozy-ivhz', 343)
very encrypted name
Using that and assuming that any ‘North Pole object’ has the word north in the name, we can update our loop:
potential_north_sectors = []
with open(args.input_file, 'r') as fin:
for room in fin:
m = re.match(r'([a-z-]+)-(\d+)\[([a-z]+)\]', room)
name, sector_id, checksum = m.groups()
if checksum != generate_checksum(name):
continue
real_name = decrypt(name, int(sector_id))
if 'north' in real_name:
potential_north_sectors.append((real_name, sector_id))
for real_name, sector_id in potential_north_sectors:
print(real_name, '@', sector_id)
It only prints a single value (for my input), so that’s good enough for me!
Don’t do this. ↩︎