Part 1: Take the relation:
F(n) = \left\{\begin{matrix}
20151225 & \textrm{if}\ n = 1 \\
252533F(n-1) \mod 33554393 & \textrm{otherwise}
\end{matrix}\right.
Arrange the values according to Cantor's diagonal argument. Find the value at a specific cell.
target_row = int(sys.argv[1])
target_col = int(sys.argv[2])
row = 1
col = 1
val = 20151125
while True:
if target_row == row and target_col == col:
print(val)
sys.exit(0)
else:
val = (val * 252533) % 33554393
if row == 1:
row = col + 1
col = 1
else:
row -= 1
col += 1
Merry Christmas!